n^2+n-3=3

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Solution for n^2+n-3=3 equation:


Simplifying
n2 + n + -3 = 3

Reorder the terms:
-3 + n + n2 = 3

Solving
-3 + n + n2 = 3

Solving for variable 'n'.

Reorder the terms:
-3 + -3 + n + n2 = 3 + -3

Combine like terms: -3 + -3 = -6
-6 + n + n2 = 3 + -3

Combine like terms: 3 + -3 = 0
-6 + n + n2 = 0

Factor a trinomial.
(-3 + -1n)(2 + -1n) = 0

Subproblem 1

Set the factor '(-3 + -1n)' equal to zero and attempt to solve: Simplifying -3 + -1n = 0 Solving -3 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1n = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1n = 0 + 3 -1n = 0 + 3 Combine like terms: 0 + 3 = 3 -1n = 3 Divide each side by '-1'. n = -3 Simplifying n = -3

Subproblem 2

Set the factor '(2 + -1n)' equal to zero and attempt to solve: Simplifying 2 + -1n = 0 Solving 2 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1n = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1n = 0 + -2 -1n = 0 + -2 Combine like terms: 0 + -2 = -2 -1n = -2 Divide each side by '-1'. n = 2 Simplifying n = 2

Solution

n = {-3, 2}

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